metaheuristics | art meta-heuristic algorithms using python | Machine Learning library

 by   thieu1995 Jupyter Notebook Version: Current License: Apache-2.0

kandi X-RAY | metaheuristics Summary

kandi X-RAY | metaheuristics Summary

metaheuristics is a Jupyter Notebook library typically used in Artificial Intelligence, Machine Learning, Numpy applications. metaheuristics has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Implement the-state-of-the-art meta-heuristic algorithms using python (numpy)
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              metaheuristics has a low active ecosystem.
              It has 227 star(s) with 82 fork(s). There are 14 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 4 have been closed. On average issues are closed in 18 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of metaheuristics is current.

            kandi-Quality Quality

              metaheuristics has 0 bugs and 0 code smells.

            kandi-Security Security

              metaheuristics has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              metaheuristics code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              metaheuristics is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              metaheuristics releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.
              It has 4418 lines of code, 274 functions and 82 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed metaheuristics and discovered the below as its top functions. This is intended to give you an instant insight into metaheuristics implemented functionality, and help decide if they suit your requirements.
            • Train the model
            • Create a random solution
            • Gets the global best best solution for a population
            • Returns the fitness for a given position
            • Compute CEC coefficient
            • Compute the CEC coefficient
            • Calculate the CEC coefficient
            • Computes the CEC_7
            • Calculates the C25 coefficient
            • Calculate CEC_4
            • Calculates C12
            • Calculate the C16 coefficient
            • Calculate C 13
            • Calculates the C11 coefficient
            • Calculates a CEC coefficient
            • Calculates the center of a given solution
            • Calculates the C17 coefficient for a given solution
            • Calculates the CEC19 coefficients
            • CEC coefficient
            • Train the model
            • Calculate C30 coefficient
            • Calculates the coefficient for a given solution
            • Calculate C26 coefficients
            • This function calculates the center of a solution
            • Calculates the C3 coefficients for a given solution
            • Calculates the C28 equation
            Get all kandi verified functions for this library.

            metaheuristics Key Features

            No Key Features are available at this moment for metaheuristics.

            metaheuristics Examples and Code Snippets

            No Code Snippets are available at this moment for metaheuristics.

            Community Discussions

            QUESTION

            Google OR-Tools TSP spanning multiple days with start/stop times
            Asked 2020-Dec-23 at 05:04

            I am using Google OR-Tools to optimize the routing of a single vehicle over the span of a several day.

            I am trying to:

            • Be able to specify the number of days over which to optimize routing.
            • Be able to specify the start location and end location for each day.
            • Be able to specify the start time and end time for each day.

            I have a set of 40 locations. For each day I want to include in my range of days for optimization, I prepend the start and end location to the matrix. So if I want to optimize for one day, I would have a total of 42 locations in my matrix. If I want to optimize for two days, I would have a total of 44 locations in my matrix. And so on. The pattern would like like this:

            ...

            ANSWER

            Answered 2020-Dec-03 at 13:59

            You may have something like that:

            Source https://stackoverflow.com/questions/65028943

            QUESTION

            How do I specify an end location for routes in Google OR-Tools?
            Asked 2020-Aug-21 at 14:29

            I have a working Vehicle Routing Problem solution implemented using Google's OR-Tools in Python. I have a time matrix of 16 locations, time windows for each location, and penalties for dropping each location. All values are in units of seconds. I am intentionally solving this with just one vehicle (essentially solving a Traveling Salesperson Problem). I am allowing the vehicle to wait at any location for as long as is needed. I have set the drop penalty extremely high for some locations because I do not want them to ever be dropped.

            Each location that is represented in the Time Matrix will have a time window, which indicates the time since the beginning of the day (28800 is the equivalent of 8:00am, and 64800 is the equivalent of 6:00pm, etc.) I set the upper bound maximum value as 64800 because there I want the vehicle to be done by 6:00pm.

            I have designated the the first location in the matrix as the start location.
            Now, I want the second location in the matrix to be the end location.

            I have referenced the OR-Tools documentation for this, but have not found success. I have also found a similar question posted on Stack Overflow, but did not find any particularly helpful responses.

            Below is my source code - it runs successfully, but does use the second location in the matrix as the end location in the solution it creates.

            Source

            ...

            ANSWER

            Answered 2020-Aug-21 at 14:29

            I received an answer for this question in the OR-Tools Google Groups forums.

            First, properly change the manager constructor code.

            Source https://stackoverflow.com/questions/63512567

            QUESTION

            How do I use Google OR Tools to add disjunctions, set penalties, and prevent certain locations from being dropped in VRPTW?
            Asked 2020-Aug-06 at 08:26

            I have a working Vehicle Routing Problem (with Time Windows) solution implemented using Google's OR Tools python library. I have a time matrix of 15 locations and time windows for each location. I also have the duration of a visit to each location baked into the cost of each visit. All values are in units of seconds. I am intentionally solving this with just one vehicle (essentially solving a Traveling Salesperson Problem).

            I am not trying to add the ability to drop locations from a solution if they are preventing a valid solution from being created. Right now, if I have the duration for each visit set to 3600 seconds, it won't be possible to visit all 15 locations. However, if I instead set the duration for each visit to 900 seconds, then a solution will be possible for all 15 locations. I want to add a disjunction to allow for a solution to be created with these large durations in place, and instead of failing, simply drop a location from the solution.

            I have some locations that I do not want to be dropped from the solution, so I have given them absurdly large penalties to ensure that they won't be dropped, while others I assign a penalty of zero. But now, all the other locations are being dropped because their penalty is zero - I assume that this is because the penalty is less than the cost of transit, but I am not completely sure if this is indeed the reason. How should I allow locations to be dropped from the solution, but prevent other locations from being droppable?

            Right now the only code I have added is:

            ...

            ANSWER

            Answered 2020-Aug-06 at 08:26
            1. To make location "mandatory" you must use the max int64 value ( 0x7FFFFFFFFFFFFFF) since solver can't overflow it will forbid it to drop this location.

            2. Since you are using your time matrix to feed the arc cost evaluator you should set your penalty around 10k otherwise solver has incentive to drop node and paying the cost than paying the transit cost.

            3. All your time window ranges should be in [0, max dimension value], here you set it to 64800 BUT you have some Time Windows with 79200 as upper bound, this can make the problem infeasible from the solver point of view so you should set the time dimension upper bound to at least 79200 IMHO.

            Source https://stackoverflow.com/questions/63275072

            QUESTION

            How do I interpret the Vehicle Routing Problem solution returned from Google OR Tools?
            Asked 2020-Aug-01 at 06:17

            I have a working Vehicle Routing Problem solution implemented using Google's OR Tools python library. I have a time matrix of 9 locations, and time windows for each location. All values are in units of seconds.

            (For example, the first time window is from 28800 to 28800. 28800 seconds is equivalent to 8:00am. I want this location, the depot, to be visited at exactly 8:00am)

            I am intentionally solving this with just one vehicle (essentially solving a Traveling Salesperson Problem). I believe that I have added my dimension correctly, but I could certainly have made a mistake with that - my intention is to allow the vehicle to wait at any location for as long as it would like, as along as it allows it to solve the vehicle routing problem. I set the upper bound maximum value as 86400 because there are 86400 seconds in a day, and I figure that would be a sufficiently high number given this data.

            Source

            ...

            ANSWER

            Answered 2020-Jul-30 at 05:06

            What I understand of this tuples is that you have

            Source https://stackoverflow.com/questions/63161785

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install metaheuristics

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/thieu1995/metaheuristics.git

          • CLI

            gh repo clone thieu1995/metaheuristics

          • sshUrl

            git@github.com:thieu1995/metaheuristics.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link